4sin^2x-(-4sin^2x+1)=2

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Solution for 4sin^2x-(-4sin^2x+1)=2 equation:


Simplifying
4sin2x + -1(-4sin2x + 1) = 2

Reorder the terms:
4in2sx + -1(1 + -4in2sx) = 2
4in2sx + (1 * -1 + -4in2sx * -1) = 2
4in2sx + (-1 + 4in2sx) = 2

Reorder the terms:
-1 + 4in2sx + 4in2sx = 2

Combine like terms: 4in2sx + 4in2sx = 8in2sx
-1 + 8in2sx = 2

Solving
-1 + 8in2sx = 2

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 8in2sx = 2 + 1

Combine like terms: -1 + 1 = 0
0 + 8in2sx = 2 + 1
8in2sx = 2 + 1

Combine like terms: 2 + 1 = 3
8in2sx = 3

Divide each side by '8n2sx'.
i = 0.375n-2s-1x-1

Simplifying
i = 0.375n-2s-1x-1

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